Answer:
Option B
Explanation:
As you can see in options, energy term is mentioned hence, we have to find out relation between h/λ and energy. For this, we shall use de-Broglie wavelength and kinetic energy term in eV. de-Broglie wavelength for an electron
$(\lambda)=\frac{h}{p}$
$p=\frac{h}{\lambda}$.........(i)
Kinetic energy ofan electron = eV
As we know that , $KE=\frac{p^{2}}{2m}$
Therefore,$eV=\frac{p^{2}}{2m}$ or $p=\sqrt{meV}$ ...{ii}
From Eqs. (i) and (ii) we get
$\frac{h}{\lambda}=\sqrt{meV}$